Two H atoms in the ground state collide inelastically.

Two H atoms in the ground state collide inelastically. The maximum amount by which their combined kinetic energy is reduced is (a) 10.20 eV    (b) 20.40eV     (c) 13.6 eV

Let two H atoms intially at in the ground state. Now two atoms collide inelastically . The total energy associated withhe two H atoms ,= 2 × (13.6eV) = 27.2 eV,The maximum amount by which their combined kinectic energy is reduced when any one of them goes inti first excited state (n =2) after the inelastic collision .,The total energy associated with the two H-atoms after the collision.,= (13.6/2,2,) + (13.6) = 17.0eV,Hence, maximum loss of their combined kinectic energy ,= 27.2 - 17.0 = 10.2eV

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