Solve the differential equation (1+y2)tan-1 x dx + 2y(1+x2)dy = 0.

Solve the differential equation (1+y2)tan-1 x dx + 2y(1+x2)dy = 0.

We have ,(1+y,2,)tan-1 xdx + 2y(1+x,2,)dy = 0,⇒ (1+y,2,)tan-1 xdx + 2y(1+x,2,)dy