Find the area enclosed by the curve y = -x2 and the straight line x+y+2 = 0.

Find the area enclosed by the curve y = -x2 and the straight line x+y+2 = 0.

We have y = -x,2, and x+y+2=0,Solving we get, ,x,2, = x+2,⇒ x,2,-x-2=0,⇒ (x-2)(x+1) = 0,⇒ x = 2,-1,The graph of above function is downward parabola.