If A = [2, λ, -3, 0, 2, 5, 1, 1, 3|, then A-1 exists if

If A = [2 λ -3 0 2 5 1 1 3| then A-1 exists if (a) λ=2(b) λ≠2(c) λ≠-2(d) None of these

A,-1, exists if |A|≠ 0,Now |A| = 2(6-5)-λ(-5)-3(-2)= 8 + 5λ,⇒ 5λ ≠ -8,⇒ λ ≠ -8/5,So, A,-1, exists if and only if ≠ -8/5.