This question was previously asked in

PTCUL AE E&M 2017 Official Paper (Set B)

- 9 km
- 12 km
- 15 km
- None of these

Option 3 : 15 km

Free

ST 1: Logical Reasoning

1263

20 Questions
20 Marks
20 Mins

In the below diagram shortest distance between starting point and destination denoted by point A and D respectively.

Given:

Distance BC = thrice distance between point A and B.

Distance CD = five times of distance he covered between A and B

Now, Triangle "AED" is a right-angled triangle, so using Pythagoras Theorem:

**DA ^{2} = AE^{2} + DE^{2 }**

**DA ^{2}** = (9)

**DA ^{2}** = 81 + 144

**DA ^{2}** = 225

**DA** = √225

**DA **= 15

Hence, the correct answer is** "15 km".**

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Trusted by 2,18,81,352+ Students

Testbook Edu Solutions Pvt. Ltd.

1st & 2nd Floor, Zion Building,

Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

[email protected]
Plot No. 273, Sector 10, Kharghar,

Navi Mumbai - 410210

Toll Free:1800 833 0800

Office Hours: 10 AM to 7 PM (all 7 days)